**You have 100kg of Martian potatoes, which are 99 percent water by weight. You let them dehydrate until they’re 98 percent water. How much do they weigh now?**

**Logic:**

Initially the non-water weight is 1kg, which is 1% of 100kg. After dehydration, 1kg is 2% of how many kilograms? In order that that percentage be twice as big, the total weight must be half as big. Therefore the weight is 50kg.

*Algebra:*

The weight of water in the fresh potatoes is 99% of 100 kg = 99kg

Let *x *be the weight of water lost when they dehydrate (i.e. *x *kg of water is lost)

So the final result is (99 – *x*) kg water

However, the final result can also be expressed as (100 – *x*) kg of potatoes which contain 98% water, that is 0.98 (100 – *x*) kg water

Equating

(99 – *x*) = 0.98 (100 – x)

99 – x = 98 – 0.98x

1 = 0.02x

x = 50

therefore 50 kg of water is lost and the potatoes weigh 50kg